4w^2-10w=24

Solution for 4w^2-10w=24 equation:

4w^2-10w=24

We move all terms to the left:

4w^2-10w-(24)=0

a = 4; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·4·(-24)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-22}{2*4}=\frac{-12}{8}
=-1+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+22}{2*4}=\frac{32}{8}
=4
$